3.4.76 \(\int \frac {\text {arctanh}(a x)^2}{\sqrt {1-a^2 x^2}} \, dx\) [376]

3.4.76.1 Optimal result

Integrand size = 21, antiderivative size = 103 \[ \int \frac {\text {arctanh}(a x)^2}{\sqrt {1-a^2 x^2}} \, dx=\frac {2 \arctan \left (e^{\text {arctanh}(a x)}\right ) \text {arctanh}(a x)^2}{a}-\frac {2 i \text {arctanh}(a x) \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )}{a}+\frac {2 i \text {arctanh}(a x) \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )}{a}+\frac {2 i \operatorname {PolyLog}\left (3,-i e^{\text {arctanh}(a x)}\right )}{a}-\frac {2 i \operatorname {PolyLog}\left (3,i e^{\text {arctanh}(a x)}\right )}{a} \]

output

2*arctan((a*x+1)/(-a^2*x^2+1)^(1/2))*arctanh(a*x)^2/a-2*I*arctanh(a*x)*pol 
ylog(2,-I*(a*x+1)/(-a^2*x^2+1)^(1/2))/a+2*I*arctanh(a*x)*polylog(2,I*(a*x+ 
1)/(-a^2*x^2+1)^(1/2))/a+2*I*polylog(3,-I*(a*x+1)/(-a^2*x^2+1)^(1/2))/a-2* 
I*polylog(3,I*(a*x+1)/(-a^2*x^2+1)^(1/2))/a
 

3.4.76.2 Mathematica [A] (verified)

Time = 0.10 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.16 \[ \int \frac {\text {arctanh}(a x)^2}{\sqrt {1-a^2 x^2}} \, dx=\frac {i \left (-\text {arctanh}(a x)^2 \left (\log \left (1-i e^{-\text {arctanh}(a x)}\right )-\log \left (1+i e^{-\text {arctanh}(a x)}\right )\right )-2 \text {arctanh}(a x) \left (\operatorname {PolyLog}\left (2,-i e^{-\text {arctanh}(a x)}\right )-\operatorname {PolyLog}\left (2,i e^{-\text {arctanh}(a x)}\right )\right )-2 \left (\operatorname {PolyLog}\left (3,-i e^{-\text {arctanh}(a x)}\right )-\operatorname {PolyLog}\left (3,i e^{-\text {arctanh}(a x)}\right )\right )\right )}{a} \]

input

Integrate[ArcTanh[a*x]^2/Sqrt[1 - a^2*x^2],x]
 

output

(I*(-(ArcTanh[a*x]^2*(Log[1 - I/E^ArcTanh[a*x]] - Log[1 + I/E^ArcTanh[a*x] 
])) - 2*ArcTanh[a*x]*(PolyLog[2, (-I)/E^ArcTanh[a*x]] - PolyLog[2, I/E^Arc 
Tanh[a*x]]) - 2*(PolyLog[3, (-I)/E^ArcTanh[a*x]] - PolyLog[3, I/E^ArcTanh[ 
a*x]])))/a
 

3.4.76.3 Rubi [A] (verified)

Time = 0.46 (sec) , antiderivative size = 90, normalized size of antiderivative = 0.87, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {6514, 3042, 4668, 3011, 2720, 7143}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\text {arctanh}(a x)^2}{\sqrt {1-a^2 x^2}} \, dx\)

\(\Big \downarrow \) 6514

\(\displaystyle \frac {\int \sqrt {1-a^2 x^2} \text {arctanh}(a x)^2d\text {arctanh}(a x)}{a}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\int \text {arctanh}(a x)^2 \csc \left (i \text {arctanh}(a x)+\frac {\pi }{2}\right )d\text {arctanh}(a x)}{a}\)

\(\Big \downarrow \) 4668

\(\displaystyle \frac {-2 i \int \text {arctanh}(a x) \log \left (1-i e^{\text {arctanh}(a x)}\right )d\text {arctanh}(a x)+2 i \int \text {arctanh}(a x) \log \left (1+i e^{\text {arctanh}(a x)}\right )d\text {arctanh}(a x)+2 \text {arctanh}(a x)^2 \arctan \left (e^{\text {arctanh}(a x)}\right )}{a}\)

\(\Big \downarrow \) 3011

\(\displaystyle \frac {2 i \left (\int \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )d\text {arctanh}(a x)-\text {arctanh}(a x) \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )\right )-2 i \left (\int \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )d\text {arctanh}(a x)-\text {arctanh}(a x) \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )\right )+2 \text {arctanh}(a x)^2 \arctan \left (e^{\text {arctanh}(a x)}\right )}{a}\)

\(\Big \downarrow \) 2720

\(\displaystyle \frac {2 i \left (\int e^{-\text {arctanh}(a x)} \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )de^{\text {arctanh}(a x)}-\text {arctanh}(a x) \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )\right )-2 i \left (\int e^{-\text {arctanh}(a x)} \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )de^{\text {arctanh}(a x)}-\text {arctanh}(a x) \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )\right )+2 \text {arctanh}(a x)^2 \arctan \left (e^{\text {arctanh}(a x)}\right )}{a}\)

\(\Big \downarrow \) 7143

\(\displaystyle \frac {2 \text {arctanh}(a x)^2 \arctan \left (e^{\text {arctanh}(a x)}\right )+2 i \left (\operatorname {PolyLog}\left (3,-i e^{\text {arctanh}(a x)}\right )-\text {arctanh}(a x) \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )\right )-2 i \left (\operatorname {PolyLog}\left (3,i e^{\text {arctanh}(a x)}\right )-\text {arctanh}(a x) \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )\right )}{a}\)

input

Int[ArcTanh[a*x]^2/Sqrt[1 - a^2*x^2],x]
 

output

(2*ArcTan[E^ArcTanh[a*x]]*ArcTanh[a*x]^2 + (2*I)*(-(ArcTanh[a*x]*PolyLog[2 
, (-I)*E^ArcTanh[a*x]]) + PolyLog[3, (-I)*E^ArcTanh[a*x]]) - (2*I)*(-(ArcT 
anh[a*x]*PolyLog[2, I*E^ArcTanh[a*x]]) + PolyLog[3, I*E^ArcTanh[a*x]]))/a
 

3.4.76.3.1 Defintions of rubi rules used

rule 2720

Int[u_, x_Symbol] :> With[{v = FunctionOfExponential[u, x]}, Simp[v/D[v, x] 
   Subst[Int[FunctionOfExponentialFunction[u, x]/x, x], x, v], x]] /; Funct 
ionOfExponentialQ[u, x] &&  !MatchQ[u, (w_)*((a_.)*(v_)^(n_))^(m_) /; FreeQ 
[{a, m, n}, x] && IntegerQ[m*n]] &&  !MatchQ[u, E^((c_.)*((a_.) + (b_.)*x)) 
*(F_)[v_] /; FreeQ[{a, b, c}, x] && InverseFunctionQ[F[x]]]
 

rule 3011

Int[Log[1 + (e_.)*((F_)^((c_.)*((a_.) + (b_.)*(x_))))^(n_.)]*((f_.) + (g_.) 
*(x_))^(m_.), x_Symbol] :> Simp[(-(f + g*x)^m)*(PolyLog[2, (-e)*(F^(c*(a + 
b*x)))^n]/(b*c*n*Log[F])), x] + Simp[g*(m/(b*c*n*Log[F]))   Int[(f + g*x)^( 
m - 1)*PolyLog[2, (-e)*(F^(c*(a + b*x)))^n], x], x] /; FreeQ[{F, a, b, c, e 
, f, g, n}, x] && GtQ[m, 0]
 

rule 3042

Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 4668

Int[csc[(e_.) + Pi*(k_.) + (Complex[0, fz_])*(f_.)*(x_)]*((c_.) + (d_.)*(x_ 
))^(m_.), x_Symbol] :> Simp[-2*(c + d*x)^m*(ArcTanh[E^((-I)*e + f*fz*x)/E^( 
I*k*Pi)]/(f*fz*I)), x] + (-Simp[d*(m/(f*fz*I))   Int[(c + d*x)^(m - 1)*Log[ 
1 - E^((-I)*e + f*fz*x)/E^(I*k*Pi)], x], x] + Simp[d*(m/(f*fz*I))   Int[(c 
+ d*x)^(m - 1)*Log[1 + E^((-I)*e + f*fz*x)/E^(I*k*Pi)], x], x]) /; FreeQ[{c 
, d, e, f, fz}, x] && IntegerQ[2*k] && IGtQ[m, 0]
 

rule 6514

Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)/Sqrt[(d_) + (e_.)*(x_)^2], x_ 
Symbol] :> Simp[1/(c*Sqrt[d])   Subst[Int[(a + b*x)^p*Sech[x], x], x, ArcTa 
nh[c*x]], x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[c^2*d + e, 0] && IGtQ[p, 0 
] && GtQ[d, 0]
 

rule 7143

Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_S 
ymbol] :> Simp[PolyLog[n + 1, c*(a + b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d 
, e, n, p}, x] && EqQ[b*d, a*e]
 

3.4.76.4 Maple [F]

\[\int \frac {\operatorname {arctanh}\left (a x \right )^{2}}{\sqrt {-a^{2} x^{2}+1}}d x\]

input

int(arctanh(a*x)^2/(-a^2*x^2+1)^(1/2),x)
 

output

int(arctanh(a*x)^2/(-a^2*x^2+1)^(1/2),x)
 

3.4.76.5 Fricas [F]

\[ \int \frac {\text {arctanh}(a x)^2}{\sqrt {1-a^2 x^2}} \, dx=\int { \frac {\operatorname {artanh}\left (a x\right )^{2}}{\sqrt {-a^{2} x^{2} + 1}} \,d x } \]

input

integrate(arctanh(a*x)^2/(-a^2*x^2+1)^(1/2),x, algorithm="fricas")
 

output

integral(-sqrt(-a^2*x^2 + 1)*arctanh(a*x)^2/(a^2*x^2 - 1), x)
 

3.4.76.6 Sympy [F]

\[ \int \frac {\text {arctanh}(a x)^2}{\sqrt {1-a^2 x^2}} \, dx=\int \frac {\operatorname {atanh}^{2}{\left (a x \right )}}{\sqrt {- \left (a x - 1\right ) \left (a x + 1\right )}}\, dx \]

input

integrate(atanh(a*x)**2/(-a**2*x**2+1)**(1/2),x)
 

output

Integral(atanh(a*x)**2/sqrt(-(a*x - 1)*(a*x + 1)), x)
 

3.4.76.7 Maxima [F]

\[ \int \frac {\text {arctanh}(a x)^2}{\sqrt {1-a^2 x^2}} \, dx=\int { \frac {\operatorname {artanh}\left (a x\right )^{2}}{\sqrt {-a^{2} x^{2} + 1}} \,d x } \]

input

integrate(arctanh(a*x)^2/(-a^2*x^2+1)^(1/2),x, algorithm="maxima")
 

output

integrate(arctanh(a*x)^2/sqrt(-a^2*x^2 + 1), x)
 

3.4.76.8 Giac [F]

\[ \int \frac {\text {arctanh}(a x)^2}{\sqrt {1-a^2 x^2}} \, dx=\int { \frac {\operatorname {artanh}\left (a x\right )^{2}}{\sqrt {-a^{2} x^{2} + 1}} \,d x } \]

input

integrate(arctanh(a*x)^2/(-a^2*x^2+1)^(1/2),x, algorithm="giac")
 

output

integrate(arctanh(a*x)^2/sqrt(-a^2*x^2 + 1), x)
 

3.4.76.9 Mupad [F(-1)]

Timed out. \[ \int \frac {\text {arctanh}(a x)^2}{\sqrt {1-a^2 x^2}} \, dx=\int \frac {{\mathrm {atanh}\left (a\,x\right )}^2}{\sqrt {1-a^2\,x^2}} \,d x \]

input

int(atanh(a*x)^2/(1 - a^2*x^2)^(1/2),x)
 

output

int(atanh(a*x)^2/(1 - a^2*x^2)^(1/2), x)